名稱空間
變體
操作

std::chrono::year::is_leap

來自 cppreference.com
< cpp‎ | chrono‎ | year
 
 
 
 
constexpr bool is_leap() const noexcept;
(C++20 起)

確定 *this 是否在 純粹格里高利曆 中表示閏年。

*this 表示閏年,如果儲存的年份值

  • 能被 4 整除但不能被 100 整除;或
  • 能被 400 整除。

[編輯] 返回值

true 如果 *this 表示閏年,否則 false

[編輯] 示例

#include <chrono>
#include <iostream>
 
int main()
{
    using namespace std::chrono_literals;
    for (const std::chrono::year y : {2020y, 2021y, 2000y, 3000y})
    {
        if (const int iy{static_cast<int>(y)}; y.is_leap())
            std::cout << iy << " is a leap year because it is divisible by "
                      << (iy % 400 == 0 ? "400\n" : "4 and not divisible by 100\n");
        else
            std::cout << iy << " is not a leap year\n";
    }
}

輸出

2020 is a leap year because it is divisible by 4 and not divisible by 100
2021 is not a leap year
2000 is a leap year because it is divisible by 400
3000 is not a leap year