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std::chrono::year_month_day_last::operator sys_days, std::chrono::year_month_day_last::operator local_days

來自 cppreference.com
 
 
 
 
constexpr operator std::chrono::sys_days() const noexcept;
(1) (C++20 起)
constexpr explicit operator std::chrono::local_days() const noexcept;
(2) (C++20 起)

*this 轉換為一個 std::chrono::time_point,表示與此 year_month_day_last 相同的日期。這等價於從 year()month()day() 組合一個 year_month_day,然後將該 year_month_day 轉換為目標型別。

1) 等價於 std::chrono::sys_days(year()/month()/day())
2) 等價於 std::chrono::local_days(year()/month()/day())

[edit] 示例

#include <array>
#include <chrono>
#include <iostream>
#include <string_view>
using namespace std::chrono;
using namespace std::literals;
 
int main()
{
    constexpr std::chrono::year y{2023y};
    constexpr std::array quarters{"1st"sv, "2nd"sv, "3rd"sv, "4th"sv};
    constexpr auto mq{12 / 4}; // months per quarter        
 
    std::cout << "In year " << static_cast<int>(y) << '\n';
    for (auto q = 1; q < 5; ++q)
    {
        const auto ls = y / std::chrono::month(q * mq) / Sunday[last];
        const auto ld = y / std::chrono::month(q * mq) / last;
        // subtract last Sunday from last day for day of week
        const auto index = (sys_days(ld) - sys_days(ls)).count();
        std::cout << "The " << quarters[q - 1] << " quarter ends on a "  
                  << std::chrono::weekday(index) << '\n';
    }
}

輸出

In year 2023
The 1st quarter ends on a Fri
The 2nd quarter ends on a Fri
The 3rd quarter ends on a Sat
The 4th quarter ends on a Sun

[edit] 參閱

轉換為 std::chrono::time_point
(std::chrono::year_month_day 的公開成員函式) [編輯]