std::filesystem::hard_link_count
來自 cppreference.com
< cpp | filesystem
定義於標頭檔案 <filesystem> |
||
std::uintmax_t hard_link_count( const std::filesystem::path& p ); |
(1) | (C++17 起) |
std::uintmax_t hard_link_count( const std::filesystem::path& p, std::error_code& ec ) noexcept; |
(2) | (C++17 起) |
返回由路徑 p 標識的檔案系統物件的硬連結數量。
無丟擲異常的過載在錯誤發生時返回 static_cast<uintmax_t>(-1)。
目錄 |
[編輯] 引數
p | - | 要檢查的路徑 |
ec | - | 非丟擲過載中用於錯誤報告的出參 |
[編輯] 返回值
路徑 p 的硬連結數量。
[編輯] 異常
任何未標記為 noexcept
的過載都可能在記憶體分配失敗時丟擲 std::bad_alloc。
[編輯] 示例
執行此程式碼
#include <filesystem> #include <iostream> namespace fs = std::filesystem; int main() { // On a POSIX-style filesystem, each directory has at least 2 hard links: // itself and the special member pathname "." fs::path p = fs::current_path(); std::cout << "Number of hard links for current path is " << fs::hard_link_count(p) << '\n'; // Each ".." is a hard link to the parent directory, so the total number // of hard links for any directory is 2 plus number of direct subdirectories p = fs::current_path() / ".."; // Each dot-dot is a hard link to parent std::cout << "Number of hard links for .. is " << fs::hard_link_count(p) << '\n'; }
可能的輸出
Number of hard links for current path is 2 Number of hard links for .. is 3
[編輯] 參閱
(C++17) |
建立硬連結 (函式) |
返回目錄項所引用檔案的硬連結數量 ( std::filesystem::directory_entry 的公開成員函式) |