std::type_info::operator==, std::type_info::operator!=
來自 cppreference.com
bool operator==( const type_info& rhs ) const; |
(1) | (C++11 起無異常丟擲) (自 C++23 起為 constexpr) |
bool operator!=( const type_info& rhs ) const; |
(2) | (C++11 起無異常丟擲) (C++20 前) |
檢查物件是否引用相同的型別。
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(C++20 起) |
目錄 |
[編輯] 引數
| rhs | - | 另一個要比較的型別資訊物件 |
[編輯] 返回值
若比較操作結果為 true,則返回 true,否則返回 false。
[編輯] 備註
| 特性測試宏 | 值 | 標準 | 特性 |
|---|---|---|---|
__cpp_lib_constexpr_typeinfo |
202106L |
(C++23) | std::type_info::operator== 的 constexpr |
[編輯] 示例
執行此程式碼
#include <iostream> #include <string> #include <typeinfo> #include <utility> class person { public: explicit person(std::string n) : name_(std::move(n)) {} virtual const std::string& name() const { return name_; } private: std::string name_; }; class employee : public person { public: employee(std::string n, std::string p) : person(std::move(n)), profession_(std::move(p)) {} const std::string& profession() const { return profession_; } private: std::string profession_; }; void print_info(const person& p) { if (typeid(person) == typeid(p)) std::cout << p.name() << " is not an employee\n"; else if (typeid(employee) == typeid(p)) { std::cout << p.name() << " is an employee "; auto& emp = dynamic_cast<const employee&>(p); std::cout << "who works in " << emp.profession() << '\n'; } } int main() { print_info(employee{"Paul","Economics"}); print_info(person{"Kate"}); #if __cpp_lib_constexpr_typeinfo if constexpr (typeid(employee) != typeid(person)) // C++23 std::cout << "class `employee` != class `person`\n"; #endif }
可能的輸出
Paul is an employee who works in Economics Kate is not an employee class `employee` != class `person`
[編輯] 參閱
檢查所引用型別是否在實現定義的順序中位於另一個 type_info 所引用型別之前,即對所引用型別進行排序。 (public 成員函式) |