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std::reverse_iterator<Iter>::base

來自 cppreference.com
 
 
迭代器庫
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(C++20)
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(C++17)(C++20)
(C++17)
(C++17)
 
 
iterator_type base() const;
(自 C++17 起為 constexpr)

返回底層迭代器。

目錄

[edit] 返回值

current

[edit] 註解

基礎迭代器指向 `reverse_iterator` 當前所指向元素的下一個元素(從 `iterator_type` 的角度看)。也就是說 &*(this->base() - 1) == &*(*this)

[edit] 示例

#include <iostream>
#include <iterator>
#include <vector>
 
int main()
{
    std::vector<int> v = {0, 1, 2, 3, 4, 5};
 
    using RevIt = std::reverse_iterator<std::vector<int>::iterator>;
 
    const auto it = v.begin() + 3;
    RevIt r_it{it};
 
    std::cout << "*it == " << *it << '\n'
              << "*r_it == " << *r_it << '\n'
              << "*r_it.base() == " << *r_it.base() << '\n'
              << "*(r_it.base() - 1) == " << *(r_it.base() - 1) << '\n';
 
    RevIt r_end{v.begin()};
    RevIt r_begin{v.end()};
 
    for (auto it = r_end.base(); it != r_begin.base(); ++it)
        std::cout << *it << ' ';
    std::cout << '\n';
 
    for (auto it = r_begin; it != r_end; ++it)
        std::cout << *it << ' ';
    std::cout << '\n';
}

輸出

*it == 3
*r_it == 2
*r_it.base() == 3
*(r_it.base() - 1) == 2
0 1 2 3 4 5
5 4 3 2 1 0

[edit] 參閱

訪問指向的元素
(public member function) [edit]