std::ranges::borrowed_iterator_t, std::ranges::borrowed_subrange_t
來自 cppreference.com
定義於標頭檔案 <ranges> |
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template< ranges::range R > using borrowed_iterator_t = /* see below */; |
(1) | (C++20 起) |
template< ranges::range R > using borrowed_subrange_t = /* see below */; |
(2) | (C++20 起) |
2) 如果
R
滿足 borrowed_range
模型,則為 std::ranges::subrange<std::ranges::iterator_t<R>>,否則為 std::ranges::dangling。這兩個別名模板被一些 受約束的演算法 用於避免返回潛在的懸空迭代器或檢視。
[編輯] 可能實現
borrowed_iterator_t |
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template< std::ranges::range R > using borrowed_iterator_t = std::conditional_t<std::ranges::borrowed_range<R>, std::ranges::iterator_t<R>, std::ranges::dangling>; |
borrowed_subrange_t |
template< std::ranges::range R > using borrowed_subrange_t = std::conditional_t<std::ranges::borrowed_range<R>, std::ranges::subrange<std::ranges::iterator_t<R>>, std::ranges::dangling>; |
[編輯] 參閱
(C++20) |
一個佔位符型別,指示迭代器或 subrange 不應返回,因為它會懸空(class) |