std::shared_ptr<T>::get
來自 cppreference.com
< cpp | 記憶體 | shared ptr
T* get() const noexcept; |
(C++17 前) | |
element_type* get() const noexcept; |
(C++17 起) | |
返回儲存的指標。
目錄 |
[編輯] 引數
(無)
[編輯] 返回值
儲存的指標。
[編輯] 注意
一個 shared_ptr
可以共享一個物件的所有權,同時儲存指向另一個物件的指標。get()
返回儲存的指標,而不是被管理的指標。
[編輯] 示例
執行此程式碼
#include <iostream> #include <memory> #include <string_view> int main() { auto output = [](std::string_view msg, int const* pInt) { std::cout << msg << *pInt << " in " << pInt << '\n'; }; int* pInt = new int(42); std::shared_ptr<int> pShared = std::make_shared<int>(42); output("Naked pointer: ", pInt); // output("Shared pointer: ", pShared); // compiler error output("Shared pointer: ", &*pShared); // OK, calls operator*, then takes addr output("Shared pointer with get(): ", pShared.get()); delete pInt; std::cout << "\nThe shared_ptr's aliasing constructor demo.\n"; struct Base1 { int i1{}; }; struct Base2 { int i2{}; }; struct Derived : Base1, Base2 { int i3{}; }; std::shared_ptr<Derived> p(new Derived()); std::shared_ptr<Base2> q(p, static_cast<Base2*>(p.get())); std::cout << "q shares ownership with p, but points to Base2 subobject:\n" << "p.get(): " << p.get() << '\n' << "q.get(): " << q.get() << '\n' << "&(p->i1): " << &(p->i1) << '\n' << "&(p->i2): " << &(p->i2) << '\n' << "&(p->i3): " << &(p->i3) << '\n' << "&(q->i2): " << &(q->i2) << '\n'; }
可能的輸出
Naked pointer: 42 in 0xacac20 Shared pointer: 42 in 0xacac50 Shared pointer with get(): 42 in 0xacac50 The shared_ptr's aliasing constructor demo. q shares ownership with p, but points to Base2 subobject: p.get(): 0xacac20 q.get(): 0xacac24 &(p->i1): 0xacac20 &(p->i2): 0xacac24 &(p->i3): 0xacac28 &(q->i2): 0xacac24
[編輯] 參閱
解引用儲存的指標 (公共成員函式) |